Question

alguém poderia me ajudar por favor,preciso pra hj​

Answer 1

Explicação passo-a-passo:

I. x² - 14x + 33 = 0

${x}^{2} - 14x + 33 = 0 \\ \\ delta = {b}^{2} - 4ac \\ delta = { (- 14)}^{2} - 4.1.33 \\ delta = 196 - 132 \\ delta = 64 \\ \\ \\ x1 = \frac{ - b + \sqrt{delta} }{2a} \\ \\ x1 = \frac{14 + 8}{2} \\ \\ x1 = \frac{22}{2} \\ \\ x1 = 11 \\ \\ \\ x2 = \frac{ - b - \sqrt{delta} }{2a} \\ \\ x2 = \frac{14 - 8}{2} \\ \\ x2 = \frac{6}{2} \\ \\ x2 = 3$

S = { 3, 11 }

II. x² + 12x + 27 = 0

${x}^{2} + 12x + 27 = 0\\ \\ delta = {b}^{2} - 4ac \\ delta = { 12}^{2} - 4.1.27 \\ delta = 144 - 108 \\ delta = 36 \\ \\ \\ x1 = \frac{ - b + \sqrt{delta} }{2a} \\ \\ x1 = \frac{ - 12 + 6}{2} \\ \\ x1 = \frac{ - 6}{2} \\ \\ x1 = - 3 \\ \\ \\ x2 = \frac{ - b - \sqrt{delta} }{2a} \\ \\ x2 = \frac{ - 12 - 6}{2} \\ \\ x2 = \frac{ - 18}{2} \\ \\ x2 = - 9$

S = { -9, -3 }

III. x² - 8x + 7 = 0

${x}^{2} - 8x + 7 = 0 \\ \\ delta = {b}^{2} - 4ac \\ delta = { (- 8)}^{2} - 4.1.7 \\ delta = 64 - 28 \\ delta = 36 \\ \\ \\ x1 = \frac{ - b + \sqrt{delta} }{2a} \\ \\ x1 = \frac{8+ 6}{2} \\ \\ x1 = \frac{14}{2} \\ \\ x1 = 7 \\ \\ \\ x2 = \frac{ - b - \sqrt{delta} }{2a} \\ \\ x2 = \frac{8 - 6}{2} \\ \\ x2 = \frac{2}{2} \\ \\ x2 = 1$

S = { 1, 7 }

IV. x² - 2x + 1 = 0

${ {x}^{2} - 2x + 1 = 0} \\ \\ delta = {b}^{2} - 4ac \\ delta = { (- 2)}^{2} - 4.1.1 \\ delta = 4 - 4 \\ delta = 0\\ \\ \\ x1 = \frac{ - b + \sqrt{delta} }{2a} \\ \\ x1 = \frac{2 + 0}{2} \\ \\ x1 = \frac{2}{2} \\ \\ x1 = 1 \\ \\ \\ x2 = \frac{ - b - \sqrt{delta} }{2a} \\ \\ x2 = \frac{2 - 0}{2} \\ \\ x2 = \frac{2}{2} \\ \\ x2 = 1$

S = { 1 }

V. 9x² + 24x + 16 = 0

$9 {x}^{2} + 24x + 16 = 0 \\ \\ delta = {b}^{2} - 4ac \\ delta = { 24}^{2} - 4.9.16 \\ delta = 576 - 576 \\ delta = 0 \\ \\ \\ x1 = \frac{ - b + \sqrt{delta} }{2a} \\ \\ x1 = \frac{ - 24 + 0}{18} \\ \\ x1 = \frac{ - 24}{18} \\ \\ x1 = - \frac{ - 4}{3} \\ \\ \\ x2 = \frac{ - b - \sqrt{delta} }{2a} \\ \\ x2 = \frac{ - 24 - 0}{18} \\ \\ x2 = \frac{ - 24}{18} \\ \\ x2 = \frac{ - 4}{3}$

S = { -4/3 }

Espero ter ajudado!

Desculpe qualquer erro.