Question

calcule x³-4x²+7x-3:x-1

Answer 1

$Usando~~o~~teorema~~do~~resto:$
$x-1=0$
$x = 1$

$1^3-4.1^2+7.1-3$
$1 -4+7-3 = 1$
$Portanto,o~~resto~~e\´~~1$
$\boxed{R(x) = 1}$