Question

c) -x² + 5 = 0 resposta

Answer 1

Explicação passo-a-passo:

$c) -x^2+5=0\\5=x^2\\x=+-\sqrt{5} \\x_1=\sqrt{5} \\x_2=-\sqrt{5} \\S=(-\sqrt{5}, \sqrt{5})$

Respondendo as outras que você pediu!

$e) -4x^2 + 9 = 0\\4x^2=9\\x^2=\frac{9}{4} \\x=+-\sqrt{\frac{9}{4} } \\x_1=\frac{3}{2} \\x_2=-\frac{3}{2}$

$f) 8x^2 + 6x = 0\\2x.(4x+3)=0\\2x=0\\x=0\\4x+3=0\\4x=-3\\x=\frac{-3}{4} \\S=(\frac{-3}{4},0)$

$g) -x^2 + 5 = 0\\x^2=5\\x=+-\sqrt{5\\}\\S=(-\sqrt{5},\sqrt{5})$

$h) x^2 - 10x = 0\\x(x-10)=0\\x=0\\x-10=0\\x=10\\S=(0,10)$

$i)x^2 = 0\\\\x=0\\S=(0)$

$j) 6x^2 + 7x = 0\\6x(x+7)=0\\6x=0\\x=0\\x+7=0\\x=-7\\S=(-7,0)$

$k) 4x^2 - 5x = 0\\x.(4x-5)=0\\x=0\\4x-5=0\\4x=5\\x=\frac{5}{4} \\S=(0,\frac{5}{4})$

$l) 7x^2 + 4x =0\\x.(7x+4)=0\\x=0\\7x+4=0\\7x=-4\\x=\frac{-4}{7} \\S=(0,\frac{-4}{7})$