Question

7) Resolve a operação de multiplicação do monômio
( - 2a² b c ) . ( 9 a b ³ c ) . ( 6 a b c ) eae qual o resusltado?

Answer 1

Resposta:

$-2a^{2}bc . 9ab^{3} c.6abc= -108a^{4} b^{5} c^{3}$

Answer 2

Oie, Td Bom?!

$= ( - 2a {}^{2} bc) \: . \: (9ab {}^{3} c) \: . \: (6abc)$

$= - 2a {}^{2} bc \: . \: 9ab {}^{3} c \: . \: 6abc$

$= - 108a {}^{2} b {}^{1} c {}^{1} a {}^{1} b {}^{3} c {}^{1} a {}^{1} b {}^{1} c {}^{1}$

$= - 108a {}^{2 + 1 + 1} b {}^{1 + 3 + 1} c {}^{1 + 1 + 1}$

$= - 108a {}^{4} b {}^{5} c {}^{3}$

Att. Makaveli1996