Question

1. determinar as coordenadas do vértice da h(x)=3x²-12x+9=0​

Answer 1

Resposta:

∆ = b² - 4 . a . c

∆ = (-12)² - 4 . 3 . 9

∆ = 144 - 108

∆ = 36

V (xv, yv)

V (- b / 2. a ; - ∆ / 4 . a)

V (- (-12) / 2 . 3; - 36 / 4 . 3)

V (12 /6 ; -36 /12)

V (2 ; - 3)

resp : (2 ; - 3)