Question

x.x.x=27
y.y.y.x=24
x.y.z.z=96
z+x.y=

Answer 1

$x^{3}=27 portanto \\ x=3$ $y^{3}.3=24$ $y^{3}= \frac{24}{3}=8portanto \\ y=2$ $3.2. z^{2} =96 portanto \\ z^{2}=16 portanto \\ z=4$ $4+3.2=4+6=10$

Answer 2

x= 3 , y = 2 , z=4
 3³=27
2³x 3 = 24
3x2x4²=96

4+3.2=10