Question

Me ajuda 1) ENCONTRE OS VALORES DAS INCÓGNITAS:

Answer 1

Olá!

Basta fazer a multiplicação do meio pelos extremos.

a)

$\dfrac{2x+4}{3} ~=~\dfrac{x-1}{4} \\ \\ \\ 4\times(2x+4)~=~3\times(x-1)\\ \\ 8x+16~=~3x-3\\ \\ 8x-3x=-3-16\\ \\ 5x=-19\\ \\ \\ \boxed{x=-\dfrac{19}{5}}$

b)

$\dfrac{3x-2}{3} ~=~\dfrac{x-1}{2} \\ \\ \\ 2\times(3x-2)~=~3\times(x-1)\\ \\6x-4~=~3x-3\\ \\ 6x-3x=-3+4\\ \\ 3x=1\\ \\ \\ \boxed{x=\dfrac{1}{3}}}$

c)

$\dfrac{5x-12}{3} ~=~\dfrac{2x-3}{2} \\ \\ \\ 2\times(5x-12)~=~3\times(2x-3)\\ \\ 10x-24~=~6x-9\\ \\ 10x-6x=-9+24\\ \\ 4x=15\\ \\ \\ \boxed{x=\dfrac{15}{4}}$

d)

$\dfrac{6x-3}{6} ~=~\dfrac{x-1}{10} \\ \\ \\ 10\times(6x-3)~=~6\times(x-1)\\ \\ 60x-30~=~6x-6\\ \\ 60x-6x=-6+30\\ \\ 54x=24\\ \\ \\x=\dfrac{24}{54}\\ \\ \\ \boxed{x=-\dfrac{4}{9}}$

:)