Question

3x²-19x+20=0 ??????????

Answer 1

Ola Edgar

3x² - 19x + 20 = 0

delta
d² = 19² - 4*3*20 = 121
d = 11

x1 = (19 + 11)/6 = 30/6 = 5
x2 = (19 - 11)/6 = 8/6 = 4/3

.