Question

Na figura, os três polígonos são regulares. Calcule o valor de a, bec.
b​

Answer 1

$a=\frac{(n-2).180°}{n}$

$a= \frac{(12-2).180°}{12}$

$a= \frac{10.180°}{12}$

$a= \frac{1800°}{12}$

a= 150°

$c= \frac{(n-2).180°}{n}$

$c= \frac{(6-2).180°}{6}$

$c= \frac{4. 180°}{6}$

$c= \frac{720°}{6}$

c= 120°

a+b+C= 360°

150°+b+120°=360°

b= 360°- 270°

b= 90°