Question

Me ajudem, por favor....

Answer 1

a) $\frac{3a^2}{b}.\frac{4b^2}{a}=\frac{12(ab)^2}{ab}=12ab$

b) $\frac{6xy}{4a^2}:\frac{9x^2}{2ab}=\frac{6xy}{4a^2}.\frac{2ab}{9x^2}=\frac{12xyab}{36(ax)^2}=\frac{12by}{36ax}=\frac{by}{3ax}$