Question

Dada a equação diofantina 4x + 8y = 32, quais pares de inteiros são soluções:

(1, 2), (2, 2) e (3, 4)
(-2, 5), (4, 2) e (2, 3)
(10,-1) , ( 2,2) e (2,3)
(2, 2), (1, 4) e ( 2, 3)
(10, -1), (2, 3) e (-3, 6)

Answer 1

(-2,5)
4*(-2)+8*(5)= 
-8+40=
32

(4,2)
4*4+8*2=
16+16=
32

(2,3)
4*2+8*3=
8+24=
32

Answer 2

(-2,5)
4*(-2)+8*(5)= 
-8+40=
32

(4,2)
4*4+8*2=
16+16=
32

(2,3)
4*2+8*3=
8+24=
32