Question

equação. Então resolva a equação do 2º grau incompleta abaixo:
a) x2 + x.(x - 6) = 0​

Answer 1

Olá!!  :)

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CÁLCULO:

   $\sf \\\\ \Rightarrow \ \ x^{2} \ + \ x \ (x \ - \ 6) \ = \ 0 \\\\ \Rightarrow \ \ x^{2} \ + \ x^{2} \ - \ 6x \ = \ 0 \\\\ \Rightarrow \ \ 2x^{2} \ - \ 6x \ = \ 0$

•  $a \ = \ 2 \ \ \ \ ; \ \ \ \ b \ = \ -6 \ \ \ \ ; \ \ \ \ c \ = \ 0$

     $\sf \Delta \ = \ b^{2} \ - \ 4ac \\\\ \Delta \ = \ (-6)^{2} \ - \ 4 \ . \ 2 \ . \ 0 \\\\ \Delta \ = \ 36$

     $\sf x' \ = \ \frac{-b \ \ + \ \ \sqrt{\Delta}}{2a} \\\\ x' \ = \ \frac{-(-6) \ + \ \sqrt{36}}{2 \ . \ 2} \\\\ x' \ = \ \frac{6 \ + \ 6}{4} \\\\ x' \ = \ \frac{12}{4} \\\\ \boxed{ \sf \ x' \ = \ 3 \ }$                     $\sf x'' \ = \ \frac{-b \ - \ \sqrt{\Delta}}{2a} \\\\ x'' \ = \ \frac{-(-6) \ - \ \sqrt{36}}{2 \ . 2} \\\\ x'' \ = \ \frac{6 \ - \ 6}{4} \\\\ x'' \ = \ \frac{0}{4} \\\\ \boxed{ \ \sf x'' \ = \ 0 \ }$

RESPOSTA:

$\sf S \ = \ \{ \ 3 \ , \ 0 \ \}$

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Espero ter ajudado, bons estudos!!  :)

•   ∫∫      Ajuda fornecida por Kimberly Carlos   ∫∫