Question

g) x² - 5x +6 = 0

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Answer 1

x² - 5x + 6 = 0

a = 1

b = -5

c = 6

Delta:

Δ = b² - 4ac

Δ = (-5)² - 4 * 1 * 6

Δ = 25 - 24

Δ = 1

     Bhaskara:

     x = - b ± √Δ / 2a

     x = - (-5) ± √1 / 2 * 1

     x = 5 ± 1 / 2

     x' = 5 + 1 / 2 = 6 / 2 = 3

     x'' = 5 - 1 / 2 = 4 / 2 = 2

S = {2, 3}