Question

qual e o numero de termo da p.g. 32,16,...1/512

Answer 1

Ola Pamella

a1 = 32
a2 = 16

q = a2/a1 = 16/32 = 1/2

termo geral

an = a1*q^(n - 1)

1/512 = 32 * (1/2)^(n - 1)

(1/2)^(n - 1) = 1/(512*32) = 1/16384

(1/2)^(n - 1) = (1/2(^14

n - 1 = 14

n = 15 termos

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