Question

CALCULE
*Os dados estão no anexo*

Answer 1

1. $n=\frac{m}{M} \\n=\frac{50}{(23+16+1)} \\n=\frac{50}{40}\\n=1,25mols$

2.$1mol_{ferro}=56g_{ferro} \\x=20g_{ferro} \\\\56x=20\\x=\frac{20}{56}\\x=0,35mols\\\\1mol=6.10^{23}atomos\\0,35mols=x\\\\x=6.0,35.10^{23}\\x=2,1.10^{23}atomos$

3.$M.M_{agua}=(2.1)+16=18g/mol\\\\1mol_{agua}=18g\\x=36\\logo, x=2mol_{agua} \\\\1mol_{agua}=6.10^{23}moleculas\\2mol_{agua}=12.10^{23}moleculas=1,2.10^{24}moleculas$