Question

1) Resolver as seguintes equações:



a) 2x - 10 = 30




b)x + 20 = 49




c) 5p -3 = 12



d) 4d + 4 = 2d + 12




e) 3m + 20 = 30 - m




f) 3 k -2k = 200




g) 3h - 40 = 12h - 20




h) 4y -3y + 20 = 50




i) 20 + 2 x + x = 30 + 20​

Answer 1

$a) 2x - 10 = 30 \\ 2x = 30 - 10 \\ 2x = 20 \\ x = \frac{20}{2} \\ x = 10 \\ b)x + 20 =49 \\ x = 49 - 20 \\ x = 29 \\c)5p - 3 = 12 \\ 5p = 15 + 3 \\ 5p = 18 \\ p = \frac{18}{5} \\ p= 3.6 \\ d)4d + 4 = 2d + 12 \\ 4d - 2d = 12 + 4 \\ 2d = 8 \\ d = \frac{8}{2} \\ d = 4 \\ e)3m + 20 = 30 - m \\3 m + m = 30 - 20 \\ 4m =10 \\ m = \frac{10}{4} \\ m = 2.5 \\ f)3k - 2k = 200 \\ k = 200 \\ g)3h - 40 = 12h - 20 \\ 3h - 12h = - 20 + 40 \\ - 9h = 20 \\ h = - \frac{20}{9} \\ h)4y - 3y + 20 = 50 \\ 4y - 3y = 50 - 20 \\ y = 30 \\ i)20 + 2x + x = 30 + 20 \\ 2x + x = 30 + 20 - 20 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10$

UFA!! Demorou, mas terminei!