Question

d) -10a^5 : 2a^5
e) (20x^2) : 4
f) (18x^3) : 3x^3
g) 6m^5 : (-2m^2)
h) 10a^2m^3 : (-5am)
i) 12a^3d^2 : 2ad
j) (27x^2y^2) : (9x^2y)
k) (+12x^2y^3) : (-3xy^2)
l) (-3ab^3) : (-ab^2)​

Answer 1

d)-10a^5 : 2a^5

-5a^5 × a^5

-5a^10

e)(20x^2) : 4

5x^2

f)(18x^3) : 3x^3

6x^3×x^3

6x^6

g) 6m^5 : (-2m^2)

-3m^3

h) 10a^2m^3 : (-5am)

-2am^2

i) 12a^3d^2 : 2ad

6a^3 d^2 ad

6a^ 4 d^3

j) (27x^2y^2) : (9x^2y)

(54x^2 y^3) ÷ (9x^2 y)

6y^2

k) (+12x^2y^3) : (-3xy^2)

-4xy

l) (-3ab^3) : (-ab^2)

3b

Espero ter ajudado ಡ ͜ ʖ ಡ.

Answer 2

Oie, Td Bom?!

d)

$\frac{ - 10a {}^{5} }{2a {}^{5} } = \frac{ - 10}{2} = - 5$

e)

$\frac{20x {}^{2} }{4} = 5x {}^{2}$

f)

$\frac{18x {}^{3} }{3x {}^{3} } = \frac{18}{3} = 6$

g)

$\frac{6m {}^{5} }{ - 2m {}^{2} } = \frac{ - 3m {}^{5} }{m {}^{2} } = - 3m {}^{3}$

h)

$\frac{10a {}^{2}m {}^{3} }{ - 5am} = \frac{ - 2a {}^{2} m {}^{3} }{ am} = \frac{ - 2am {}^{3} }{m} = - 2am {}^{2}$

i)

$\frac{12a {}^{3} d {}^{2} }{2ad } = \frac{6a {}^{3}d {}^{2} }{ad} = \frac{6a {}^{2}d {}^{2} }{d} = 6a {}^{2} d$

j)

$\frac{27x {}^{2}y {}^{2} }{9x {}^{2}y } = \frac{27y {}^{2} }{9y} = \frac{3y {}^{2} }{y} = 3y$

k)

$\frac{12x {}^{2}y {}^{3} }{ - 3xy {}^{2} } = \frac{ - 4x {}^{2} y {}^{3} }{xy {}^{2} } = \frac{ - 4xy {}^{2} }{y {}^{2} } = - 4xy$

l)

$\frac{ - 3ab {}^{3} }{ - ab {}^{2} } = \frac{ - 3 \: . \: ( - 1)b {}^{3} }{b {}^{2} } = - 3 \: . \: ( - 1)b = 3b$

Att. Makaveli1996