Question

Dado log 2=0,3010 e log 3= 0,4771 calcule Por favor me ajude
A) log 8/ log 9
B) Log 12 + log 6
C) Log 4+ log 24
D) Log 16 + log 2
E) log 4 - log 2
J) log 18- log 9

Answer 1

Ola destruidor 

a) log(8)/log(9) 

log(8) = 3*log(2) = 0.903 
log(9) = 2*log(3) = 0.954 

0.903 /0.954 = 0.947 

b) log(12) + log(6) 

log(12) = 2log(2) + log(3) = 1.079 
log(6) = log(2) + log(3) = 0.778 

1.079  + 0.778  = 1.857 

c) log(4) + log(24) = 4log(2( + log(6) = 

1.204 +  0.778  = 1.982 

d) log(16) + log(2) = 5log(2) = 1.505

e) log(4) - log(2) = 2log(2) - log(2) = log(2) = 0.301

f) log(18)- log(9) = log(18/9) = log(2) = 0.301

.

Answer 2

A)  log 8/log 9

log 8= log 2.2.2=0,903

log 9= log 3.3= 0,9542

log 8/log 9= 0,903-0,9452