Question

Calculé:

A) (6+5i)+(2-1)=

B) (6-1)-(8-2i)=

C) (4i-7)+(4+2i)=

D) (-2+i)-(5-3i)=

E) (5+i).(2-i)=

F) (5+2i).(3-5i)=

G) (4-3i).(5i-2)=

H) (4+I)²=

Answer 1

Explicação passo-a-passo:

a)

(6 + 5i) + (2 - i)

= 6 + 5i + 2 - i

= 6 + 2 + 5i - i

= 8 + 4i

b)

(6 - i) - (8 - 2i)

= 6 - i - 8 + 2i

= 6 - 8 - i + 2i

= -2 + i

c)

(4i - 7) + (4 + 2i)

= 4i - 7 + 4 + 2i

= -7 + 4 + 4i + 2i

= -3 + 6i

d)

(-2 + i) - (5 - 3i)

= -2 + i - 5 + 3i

= -2 - 5 + i + 3i

= -7 + 4i

e)

(5 + i).(2 - i)

= 10 - 5i + 2i - i²

= 10 - 5i + 2i - (-1)

= 10 - 5i + 2i + 1

= 10 + 1 - 5i + 2i

= 11 - 3i

f)

(5 + 2i).(3 - 5i)

= 15 - 25i + 6i - 10i²

= 15 - 25i + 6i - 10.(-1)

= 15 - 25i + 6i + 10

= 15 + 10 - 25i + 6i

= 25 - 19i

g)

(4 - 3i).(5i - 2)

= 20i - 8 - 15i² + 6i

= 20i - 8 - 15.(-1) + 6i

= 20i - 8 + 15 + 6i

= -8 + 15 + 20i + 6i

= 7 + 26i

h)

(4 + i)² = 4² + 2.4.i + i²

(4 + i)² = 16 + 8i - 1

(4 + i)² = 16 - 1 + 8i

(4 + i)² = 15 + 8i