Question

Determine o valor de x:

Answer 1

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$\sf 4^2=x\cdot(x+6)\\\sf x^2+6x=16\\\sf x^2+6x-16=0\\\sf\Delta=b^2-4ac\\\sf\Delta=6^2-4\cdot1\cdot(-16)\\\sf\Delta=36+64\\\sf\Delta=100\\\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\sf x=\dfrac{-6\pm\sqrt{100}}{2\cdot1}\\\sf x=\dfrac{-6\pm10}{2}\\\sf x=\dfrac{-6+10}{2}=\dfrac{4}{2}=2\checkmark$