Question

Determine a fórmula percentual do etanol (C₂H₆O). (C = 12; H = 1; O = 16)

Answer 1

Caso tenha problemas para visualizar a resposta experimente abrir pelo navegador https://brainly.com.br/tarefa/36057396

                                                                                               

$\boxed{\begin{array}{c}\sf c\acute alculo~da~massa~molar:\end{array}}\\\sf m_{C_2H_6O}=2\cdot12+6\cdot1+16=46~g/mo\ell\\\boxed{\begin{array}{c}\sf c\acute alculo~do~percentual~de~cada~elemento:\end{array}}\\\sf C:~\dfrac{24}{46}\cdot100\%=52,17\%\\\sf H:\dfrac{6}{46}\cdot100\%=13,04\%\\\sf O:\dfrac{16}{46}\cdot100\%=34,78\%\\\rm a~f\acute ormula~percentual~da~gasolina~\acute e:\\\large\boxed{\boxed{\boxed{\boxed{\sf C_{52,17\%}H_{13,04\%}O_{34,78\%}\checkmark}}}}$