Question

Se y = x-1 / 2x + 3 então dy é / dx

Answer 1

$y = \frac{x - 1}{2x + 3}$

$y' = \frac{(2x + 3) - 2(x - 1)}{ (2x + 3)^{2} }$

$y' = \frac{2x + 3 - 2x + 2}{ (2x +3)^{2} }$

$y' = \frac{5}{ (2x + 3)^{2} }$