• Matéria: Matemática
  • Autor: Anônimo
  • Perguntado 5 anos atrás

1)Efetue as operações indicadas e simplifique se possível.

a)1/4 + 5/4 =

b)7/9 + 1/9 =

c)18/11 + 4/11 =

d)1/4 + 1/2 =

e)2/8 + 1/4 =

f)1/4 - 1/6 =

g)1/3 + 2/3 + 4/3 =

h)9/4 - 1/4 - 3/4 =

i)4/5 + 5/2 + 5/6 =



Urgente, é pra hoje!!
Valendo 15 pontos!!!
j)8/15 + 4/15 + 1/5 =​

Respostas

respondido por: rodrigosilva7236
1

Resposta:

a= 6/4 simplifique por 2

b= 8/9

c= 22/11

d= 3/4

e= 4/8 simplifique por 2

f=1/12

g = 7/3

h = 5/4

i = 124/30  simplifique 2

j=15/15 = 1

Explicação passo-a-passo:


Anônimo: e simplifica por 4
respondido por: Anônimo
1

Explicação passo-a-passo:

a)

\sf \dfrac{1}{4}+\dfrac{5}{4}

\sf =\dfrac{1+5}{4}

\sf =\dfrac{6}{4}

\sf =\dfrac{6\div2}{4\div2}

\sf =\red{\dfrac{3}{2}}

b)

\sf \dfrac{7}{9}+\dfrac{1}{9}

\sf =\dfrac{7+1}{9}

\sf =\red{\dfrac{8}{9}}

c)

\sf \dfrac{18}{11}+\dfrac{4}{11}

\sf =\dfrac{18+4}{11}

\sf =\dfrac{22}{11}

\sf =\red{2}

d)

\sf \dfrac{1}{4}+\dfrac{1}{2}

\sf mmc(4,2)=4

\sf \dfrac{1}{4}+\dfrac{1}{2}

\sf =\dfrac{1\cdot1+2\cdot1}{4}

\sf =\dfrac{1+2}{4}

\sf =\red{\dfrac{3}{4}}

e)

\sf \dfrac{2}{8}+\dfrac{1}{4}

\sf mmc(8,4)=8

\sf \dfrac{2}{8}+\dfrac{1}{4}

\sf =\dfrac{1\cdot2+2\cdot1}{8}

\sf =\dfrac{2+2}{8}

\sf =\dfrac{4}{8}

\sf =\dfrac{4\div4}{8\div4}

\sf =\red{\dfrac{1}{2}}

f)

\sf \dfrac{1}{4}-\dfrac{1}{6}

\sf mmc(4,6)=12

\sf \dfrac{1}{4}-\dfrac{1}{6}

\sf =\dfrac{3\cdot1-2\cdot1}{12}

\sf =\dfrac{3-2}{12}

\sf =\red{\dfrac{1}{12}}

g)

\sf \dfrac{1}{3}+\dfrac{2}{3}+\dfrac{4}{3}

\sf =\dfrac{1+2+4}{3}

\sf =\red{\dfrac{7}{3}}

h)

\sf \dfrac{9}{4}-\dfrac{1}{4}-\dfrac{3}{4}

\sf =\dfrac{9-1-3}{4}

\sf =\red{\dfrac{5}{4}}

i)

\sf \dfrac{4}{5}+\dfrac{5}{2}+\dfrac{5}{6}

\sf mmc(2,5,6)=30

\sf \dfrac{4}{5}+\dfrac{5}{2}+\dfrac{5}{6}

\sf =\dfrac{6\cdot4+15\cdot5+5\cdot5}{30}

\sf =\dfrac{24+75+25}{30}

\sf =\dfrac{124}{30}

\sf =\dfrac{124\div2}{30\div2}

\sf =\red{\dfrac{62}{15}}

j)

\sf \dfrac{8}{15}+\dfrac{4}{15}+\dfrac{1}{5}

\sf mmc(5,15)=15

\sf \dfrac{8}{15}+\dfrac{4}{15}+\dfrac{1}{5}

\sf =\dfrac{8\cdot1+4\cdot1+3\cdot1}{15}

\sf =\dfrac{8+4+3}{15}

\sf =\dfrac{15}{15}

\sf =\red{1}

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