Question

- Dados log 2 = n e log 3 = m, determine: a) Log 6 b) Log 48 c) Log 2/3


com a resolução*​

Answer 1

logc a^b = blogc a

logc (a . b) = logc a + logc b

a)

log 6

log (2 . 3)

log 2 + log 3

m + n

b)

log 48

log (2^4 . 3)

log 2^4 + log 3

4log 2 + log 3

4n + m

c)

log 2/3

log (2 . 3^(- 1))

log 2 + log 3^(- 1)

log 2 - log 3

n - m

Resposta:

a) m + n

b) 4n + m

c) n - m