Question

B) x² + 24 = 0.

C) 5x² = 0.
​

Answer 1

Resposta:

B)

${x}^{2} + 24 = 0 \\ \\ {x}^{2} = - 24 \\ \\ x = \frac{ + }{} \sqrt{ - 24} \\ \\ x = \frac{ + }{} \sqrt{24} \times \sqrt{ - 1} \\ \\ x = \frac{ + }{} \sqrt{24} \: \: i\\ \\ x=\frac{+}{}\sqrt{4×6}\:i\\ \\ x = \frac{+}{}\sqrt{4}×\sqrt{6}\:i\\ \\\blue{x = \frac{+}{}2\sqrt{6}\:i}$

C)

$5 {x}^{2} = 0 \\ \\ {x}^{2} = \frac{0}{5} \\ \\ {x}^{2} = 0 \\ \\ {x = \frac{ + }{} \sqrt{0} } \\ \\ \blue{x = \frac{ + }{} \: 0 = > x = 0}$