Question

usando a formula bhaskara  determine o conjunto soluçao de cada :

a)x(ao quadrado)-7+6=0 cmo respondo isso?

Answer 1

X²-7X+6=0
A=1 B=-7 C=6

Δ=(-7)²-4.1.6
Δ=49-24
Δ=25

√25=5

$\frac{-b+ou-5}{2.a} \\ \frac{x^{l}=7+5 }{2} = \frac{12}{2}=6 \\ \frac{x^{ll=7-5} }{2}= \frac{2}{2}=1$

Answer 2

x² - 7x + 6 = 0

a = 1      b = - 7      c= + 6
Δ = b² - 4.a.c
Δ = (-7)² - 4.(1).(+6)
Δ = 49  - 24
Δ = 25

x= -b ± √Δ
        2.a

x = -(-7) ± √25
           2.1

x= +7 ±  5
        2

x'= 7 + 5 = 12  = 6
        2       2

x"= 7 - 5=  2   =  1
        2      2

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