Question

Dada a função f: R->R tal que

. { x^2-2x, para x<5
f(x)= {3x-20, para 5≤x<9, determine
. {-x^2+4x-2, para x≥9

a) f(6)
b) f(-1)
c) f(10)
d) f(9)
e) f(5)
f) f(0)
g) f(4)

Answer 1

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$\sf f:\mathbb{R}\longrightarrow\mathbb{R}~tal~que\\\tt f(x)=\begin{cases}\sf x^2-2x,para~x<5\\\sf 3x-20,para~5\leq x<9\\\sf-x^2+4x-2,para~x\geq 9\end{cases}\\\sf determine:\\\tt a)~\sf f(6)\\\tt b)~\sf f(-1)\\\tt c)~\sf f(10)\\\tt d)~\sf f(9)\\\tt e)~\sf f(5)\\\tt f)~\sf f(0)\\\tt g)~\sf f(4)$

solução:

$\tt a)~\sf f(6)=3\cdot6-20=18-20=-2\checkmark\\\tt b)~\sf f(-1)=(-1)^2-2\cdot(-1)=1+2=3\checkmark\\\tt c)~\sf f(10)=-10^2+4\cdot10-2=-100+40-2=-62\checkmark\\\tt d)~\sf f(9)=-9^2-4\cdot9-2=-81-36-2=-119\checkmark\\\tt e)~\sf f(5)=3\cdot 5-20=15-20=-5\checkmark\\\tt f)~\sf f(0)=0^2-2\cdot0=0\checkmark\\\tt g)~\sf f(4)=4^2-2\cdot4=16-8=8\checkmark$