Question

resolva a equação logaritmica:

log2 (x2+ x-4)= 3​

Answer 1

log2 (x2+ x-4)= 3

(x²+x-4) = 2³

x²+x-4 -8 = 0

x² +x -12 = 0. => b/c= 1/-12 = 4-3/4•-3 ↓

(x +4 ).(x -3) = 0

x'= -4 , x"=3