Question

Calcule o vértice da função Y=x²+16x+39:

Answer 1

Explicação passo-a-passo:

$\sf y=x^2+16x+39$

• $\sf x_V=\dfrac{-b}{2a}$

$\sf x_V=\dfrac{-16}{2\cdot1}$

$\sf x_V=\dfrac{-16}{2}$

$\sf \red{x_V=-8}$

• $\sf y_V=\dfrac{-\Delta}{4a}$

$\sf \Delta=16^2-4\cdot1\cdot39$

$\sf \Delta=256-156$

$\sf \Delta=100$

$\sf y_V=\dfrac{-100}{4\cdot1}$

$\sf y_V=\dfrac{-100}{4}$

$\sf \red{y_V=-25}$

O vértice é $\sf V(-8,-25)$