Question

7 - Qual a área do sólido abaixo?​

Answer 1

Explicação passo-a-passo:

Área Total: At = 2ab+2bc+2ac

a = 4x

b = x

c = 2x+1

At = 2ab+2bc+2ac

2(4x*x)+2(x*2x+1)+2(4x*2x+1) = 0

2(4x^2)+2(2x^2+x)+(8x^2+4x) = 0

8x^2+4x+4x^2+2x+8x^2+4x = 0

8x^2+8x^2+4x^2+4x+4x+2x = 0

20x^2+10x = 0

a = 20

b = 10

c = 0

x = -b+-✓b^2-4*a*c

2*a

x = -10+-✓10^2-4*20*0

2*20

x = -10+-✓100-0

40

x = -10+-✓100-0

40

x' = -10+10

40

x' = 0

x'' = -10-10

40

x'' = -20/40 (simplificar)

x" = 1/2 ou x" = 0,5

Usar na At = 2ab+2bc+2ac

At = 2ab+2bc+2ac

At = 2(4x*x)+2(x*2x+1)+2(4x*2x+1)

At = 2*(4*0,5*0,5)+2*(0,5*2*0,5+1)+2*(4*0,5*2*0,5+1)

At = 2*(1)+2*(1,5)+2*(3)

At = 2+3+6

At = 11 cm2