Question

Me ajuda, é urgente .
Seja a função f: R-->R, dada por f(x)= (1/2)* (OBS: Substitua o '*' por 'x') Determine no caderno.
a) f(0)
b) f(4)
c) f(1)
d) f(2)
e) f(1/4)
​

Answer 1

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$\rm\large\green{\boxed{ \ \ \ \red{ a) }\ \blue{ f(0) = 1 } \ \ \ }}$

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$\rm\large\green{\boxed{ \ \ \ \red{ b) }\ \blue{ f(4) = \dfrac{1}{16}  } \ \ \ }}$

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$\rm\large\green{\boxed{ \ \ \ \red{ c) }\ \blue{ f(1) = \dfrac{1}{2} } \ \ \ }}$

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$\rm\large\green{\boxed{ \ \ \ \red{ d) }\ \blue{ f(2) = \dfrac{1}{4} } \ \ \ }}$

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$\rm\large\green{\boxed{ \ \ \ \red{ e) }\ \blue{ f(1/4) = \dfrac{1}{\sqrt[4]{2}} } \ \ \ }}$

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$\bf\large\green{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad}}$

$\green{\rm\underline{EXPLICAC_{\!\!\!,}\tilde{A}O\ PASSO{-}A{-}PASSO\ \ \ }}$✍

❄☃ $\sf(\gray{+}\ \red{cores}\ \blue{com}\ \pink{o}\ \orange{App}\ \green{Brainly})$ ☘☀

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☺lá, Diogo, como tens passado nestes tempos de quarentena⁉ E os estudos à distância, como vão⁉ Espero que bem❗

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☔ Acompanhe a resolução abaixo, feita através de algumas manipulações algébricas, e após o resultado você encontrará um link com mais informações sobre

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✈ Potenciação e radiciação;

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que talvez te ajude com exercícios semelhantes no futuro. ✌

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$\rm\large\red{\boxed{\pink{\boxed{\begin{array}{rcl} & & \\ & \orange{ f(x) = \left( \dfrac{1}{2} \right)^x } & \\ & & \\ \end{array}}}}}$

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$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad}}$

Ⓐ$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad}}$✍

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$\large\gray{\boxed{\rm\blue{ f(0) }}}$

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➡ $\sf \large \blue{ f(0) = \left( \dfrac{1}{2} \right)^0 }$

➡ $\sf \large \blue{ f(0) = 1 }$

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$\rm\large\green{\boxed{ \ \ \ \red{ a) }\ \blue{ f(0) = 1 } \ \ \ }}$ ✅

Ⓑ$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad}}$✍

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$\large\gray{\boxed{\rm\blue{ f(4) }}}$

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➡ $\sf \large \blue{ f(4) = \left( \dfrac{1}{2} \right)^4 }$

➡ $\sf \large \blue{ f(4) = \left( \dfrac{1}{2} \right) \cdot \left( \dfrac{1}{2} \right) \cdot \left( \dfrac{1}{2} \right) \cdot \left( \dfrac{1}{2} \right)}$

➡ $\sf \large \blue{ f(4) = \dfrac{1}{16} }$

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$\rm\large\green{\boxed{ \ \ \ \red{ b) }\ \blue{ f(4) = \dfrac{1}{16} } \ \ \ }}$ ✅

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Ⓒ$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad}}$✍

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$\large\gray{\boxed{\rm\blue{ f(1) }}}$

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➡ $\sf \large \blue{ f(1) = \left( \dfrac{1}{2} \right)^1 }$

➡ $\sf \large \blue{ f(1) = \dfrac{1}{2} }$

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$\rm\large\green{\boxed{ \ \ \ \red{ c) }\ \blue{ f(1) = \dfrac{1}{2} } \ \ \ }}$ ✅

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Ⓓ$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad}}$✍

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$\large\gray{\boxed{\rm\blue{ f(2) }}}$

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➡ $\sf \large \blue{ f(2) = \left( \dfrac{1}{2} \right)^2 }$

➡ $\sf \large \blue{ f(2) = \left( \dfrac{1}{2} \right) \cdot \left( \dfrac{1}{2} \right) }$

➡ $\sf \large \blue{ f(2) = \dfrac{1}{4} }$

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$\rm\large\green{\boxed{ \ \ \ \red{ d) }\ \blue{ f(2) = \dfrac{1}{4} } \ \ \ }}$ ✅

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Ⓔ$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad}}$✍

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$\large\gray{\boxed{\rm\blue{ f(1/4) }}}$

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➡ $\sf \large \blue{ f(1/4) = \left( \dfrac{1}{2} \right)^{\frac{1}{4}} }$

➡ $\sf \large \blue{ f(1/4) = \sqrt[4]{\left( \dfrac{1}{2} \right)} }$

➡ $\sf \large \blue{ f(1/4) = \dfrac{1}{\sqrt[4]{2}} }$

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$\rm\large\green{\boxed{ \ \ \ \red{ e) }\ \blue{ f(1/4) = \dfrac{1}{\sqrt[4]{2}} } \ \ \ }}$ ✅

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$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad}}$

✈ Potenciação e radiciação (https://brainly.com.br/tarefa/36120526);

$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad}}$✍

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$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad}}$☁

☕ $\bf\large\blue{Bons\ estudos.}$

($\orange{D\acute{u}vidas\ nos\ coment\acute{a}rios}$) ☄

$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad }}\LaTeX$✍

❄☃ $\sf(\gray{+}\ \red{cores}\ \blue{com}\ \pink{o}\ \orange{App}\ \green{Brainly})$ ☘☀

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$\large\textit{"Absque\ sudore\ et\ labore}$

$\large\textit{nullum\ opus\ perfectum\ est."}$