Question

1- Determinar a razão das P.G.:

a) ( 1, 3, 9,...)

b) ( -2, -4, -8,...)

c) (10, 20, 40,...)

d) ( 5, 15, 45,...)​

Answer 1

Resposta:

a)(2,6,18...)-->q=a2/a1q=6/2>q=3

b)(5,15,45....)--->q=a2/a1--->q15/5...>q=3

c)(-15,3,...)-->q=a2>a1...>q=-3/-12:3/3->q=1/4

d)(7,14,28,...)--->q=a2/a1-->q=14/7>q=2

Answer 2

Resposta:

a) ( 1, 3, 9,...) razão (q) = 3

b) ( -2, -4, -8,...) razão (q) = 2

c) (10, 20, 40,...) razão (q) = 2

d) ( 5, 15, 45,...) razão (q) = 3

Explicação passo-a-passo:

a) 9÷3= 3, 3÷1=3, *logo a razão (q) = 3*

b) (-8)÷(-4)= 2, (-4)÷(-2)= 2, *logo a razão (q) = 2*

c) 40÷20= 2, 20÷10= 2, *logo a razão (q) = 2*

d) 45÷15= 3, 15÷5= 3, *logo a razão (q) = 3*