Question

f(x) = x² + 4x -3 com q formula de Bhaskar

Answer 1

Resposta:

x = -b ± √Δ / 2a

a = 1

b = 4

c = -3

Δ = b² - 4.a.c

Δ = 16 - 4.1.(-3)

Δ = 16 + 12

Δ = 28

x = -4 ± √28 / 2.1

x1 = -4 + √28 / 2

x2 = -4 + √28 / 2