Question

log 16 na base 2 - log 32 na base 4

Answer 1

Ola Vitoria

log2(16) - log4(32) =

log2(2^4)- log2(2^5)/2log(2) = 

4  - 5/2 = 8/2 - 5/2 = 3/2 

.

Answer 2

log2(16)=x | log4(32)=y
16=2^x | 32=4^y
2^4=2^x | 2^5=(2^2)^y
4=x | 5=2y -> y=5/2

4-5/2 = 3/2 ou 1,5