Question

usando log2= 0,3, log3=0,5 e log5=0,7,determine:
Log6

Log15

Log2 5

Answer 1

Ola rrss

log(6) = log(2*3) = log(2) + log(3) = 0.2 + 0.5 = 0.7

log(15) = log(3*5) = log(3) + log(5) = 0.5 + 0.7 = 1.2

log2(5) = log(5)/log(2) = 0.7/0.3 = 7/3 = 2.33

.

.