Question

simplifique as fraçoes algebricas

a) 18x^2yz^3 / 54xy^3z
b)x / x^2 - xy
c)3x^2 y+6xy / x+ 2
d) x^2 + x / x^2 - 1​

Answer 1

Oie, Td Bom?!

a)

$= \frac{18x {}^{2} yz {}^{3} }{54x y{}^{3} z}$

$= \frac{18xyz {}^{3} }{54y {}^{3} z}$

$= \frac{18xyz {}^{2} }{54y {}^{3} }$

$= \frac{xyz {}^{2} }{3y {}^{3} }$

$= \frac{xz {}^{2} }{3y {}^{2} }$

b)

$= \frac{x}{x {}^{2} - xy}$

$= \frac{x}{x \: . \: (x - y)}$

$= \frac{1}{x - y}$

c)

$= \frac{3x {}^{2} y + 6xy}{x + 2}$

$= \frac{3xy \: . \: (x + 2)}{x + 2}$

$= 3xy$

d)

$= \frac{x {}^{2} + x}{x {}^{2} - 1}$

$= \frac{x \: . \: (x + 1)}{(x - 1) \: . \: (x + 1)}$

$= \frac{x}{x - 1}$

Att. Makaveli1996

Answer 2

Vamos lá :

a)

(18x²yz³)/(54xy³z)  = (18xyz(xz²))/(18xyz(3y²)) = xz²/3y²

b)

x /(x² - xy) = x/(x(x - y))  = 1/(x - y)

c)

(3x²y + 6xy)/(x + 2 ) = (3xy(x + 2))/(x + 2) = 3xy

d)

(x² + x)/(x² - 1)​ = (x(x + 1))/((x + 1)(x - 1)) = x/(x - 1)

Espero ter ajudado !!!