Question

Determinar as raízes da função f(x) = 9x2 - 12x + 4.

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~9x^{2}-12x+4=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=9{;}~b=-12~e~c=4\\\\\Delta=(b)^{2}-4(a)(c)=(-12)^{2}-4(9)(4)=144-(144)=0\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-12)-\sqrt{0}}{2(9)}=\frac{12-0}{18}=\frac{12\div6}{18\div6}=\frac{2}{3}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-12)+\sqrt{0}}{2(9)}=\frac{12+0}{18}=\frac{12\div6}{18\div6}=\frac{2}{3}\\\\\S=\{\frac{2}{3},~\frac{2}{3}\}$