Question

Qual o delta de 9ײ - 12×+4=0

Answer 1

Resposta:

9x² - 12x + 4 = 0

(A=9, B= -12, C=4)

∆= b² - 4ac

∆=(-12)² - 4 . 9 .4

∆=144 - 144

∆=0

x=-b ± √∆ / 2a

x= - (-12) ± √0 / 2 . 9

×= 12 ± 0 / 18

x'=

x''=

S=