Question

determine o limite a seguir

Answer 1

$\lim_{x \to \frac{1}{2} } \frac{4x^{2} -1}{2x-1} \\ \lim_{x \to \frac{1}{2} } \frac{(2x -1)(2x + 1)}{2x-1}\\\lim_{x \to \frac{1}{2} } (2x + 1) = 2*\frac{1}{2}+1 = 2$

Answer 2

Resposta:

$lim_{x - > \frac{1}{2} }( \frac{4 {x}^{2} - 1}{2x - 1} ) \\ \\ lim _{x - > \frac{1}{2} }( \frac{(2x + 1)(2x - 1)}{(2x - 1)} ) \\ \\ lim _{x - > \frac{1}{2} }( 2x + 1) \\ \\ 2( \frac{1}{2} ) + 1 = \\ \\ 1 + 1 = \\ \\ \blue{2}$

Bons Estudos!