Question

reparta 91 em partes inversamente proporcionais a 1/3 1/4 e 1/6

Answer 1

$\dfrac{a}{3} = \dfrac{b}{4} = \dfrac{c}{6} =k~ (constante~de~proporcionalidade) \\ \\\to a=3k;b=4k;c=6k \\ a+b+c=91\to 3k+4k+6k=91 \to 13k=91\to k= \dfrac{91}{13}~~ \therefore k=7 \\ \\ a=3k=3.7~\therefore a=21;b=4k=4.7~\therefore~b=28;~c=6k=6.7~\therefore~c=42\\ Logo~os~numeros ~sao ~respectivamente :21;28~e~ 42$