Question

escreva a equação da reta que passa pelos pontos A(-1,2) e B(1,3) na forma reduzida

Answer 1

$m= \frac{y-y_0}{x-x_0} = \frac{1}{2} \\ y-2=( \frac{1}{2})(x+1) \\ 2y-4=x+1$
$y= \frac{x+5}{2}$

Answer 2

$A ~(-1 ; 2) ~~ e~~ B~ (1 ; 3)\\\\ 1\°~~ passo: ~~Calcular ~~Coeficiente ~~Angular~~ m$



$m= \dfrac{y_b-y_a}{x_b-x_a} \to~~m= \dfrac{3-2}{1-(-1)} \to~~m= \dfrac{1}{1+1} \to~~\boxed{m= \dfrac{1}{2} }$



$(y-y\°)=m~(x-x\°)\\\\\\ Usando ~~o ~~Ponto ~~A~(-1~;~2)\\\\\\ (y-2)=\dfrac{1}{2}~(x-(-1))\to\\\\ (y-2)=\dfrac{1}{2}~(x+1)\to\\\\ y-2=\dfrac{x+1}{2}\to\\\\ multiplique~~ cruzado:\\\\ 2y-4=x+1\to\\\\ 2y=x+1+4\to\\\\ 2y=x+5\to\\\\ \large\boxed{\boxed{y= \dfrac{x+5}{2} }}$