Question

me ajudem porfavor !1- utilizando o Teorema de Pitágoras encontre o valor de x em cada caso:





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Answer 1

Resposta:

Explicação passo-a-passo:

a)$x^{2} =21^{2} +28^{2}$

$x^{2} =447+784$

$x^{2} =1225$

$x=\sqrt{1225}$

$x=$ ±$35$

b)$25^{2} =x^{2} +24^{2}$

$625=x^{2} +576$

$-x^{2} = 576-625$

$-x^{2} = -49$

$x^{2} =49$

$x=$±$7$

c)$x^{2} =24^{2} + 32^{2}$

$x^{2} = 576+1024$

$x^{2} =1600$

$x=\sqrt{1600}$

$x=$±$40$

d)$x^{2} =6^{2}+8^{2}$

$x^{2} =36+64$

$x^{2}=100$

$x=$±10

e)$5^{2} =4^{2} +x^{2}$

$25=16+x^{2}$

$x^{2} =25-16$

$x^{2} =9$

$x=\sqrt{9}$

$x=$±$3$

f)$x^{2} =9^{2} +12^{2}$

$x^{2} =81+144$

$x^{2} =25$

$x=\sqrt{225}$

$x=$±$15$