Question

Sendo P(x)≡3x²+2x-4 , calcule [P(x)]^2​

Answer 1

Dispositivo Briot-Ruffini

p(x) = 2x³-3x²+x+2

h(x)=2x-1  

==>2x-1=0 ==>x-1/2=0 ==>x=1/2

      |   2   |    -3    |   1  | 2

1/2   |   2   |    -2    |   0  | 2

2x³-3x²+x+2 =Q(x)*D(x) + Resto

2x³-3x²+x+2 =(2x²-2x)*(x-1/2) + 2

2x³-3x²+x+2 =(2x²-2x)*(1/2)*(2x-1) + 2

2x³-3x²+x+2 =(x²-x)*(2x-1) + 2

Q(x)=x²-x

resto=2