• Matéria: Matemática
  • Autor: kellenrodrigues109
  • Perguntado 5 anos atrás

h) (3x-1 y )²
6

i) (2x²+3xy)²


j) (1 x²y+1).(1x²y-1)
4 4 auguem me ajuda ​

Respostas

respondido por: Makaveli1996
2

Oie, Td Bom?!

h)

 = (3x - 1y) {}^{2}

 = (3x - y) {}^{2}

 = (3x) {}^{2} -  2 \: . \: 3xy + y {}^{2}

 = 9x {}^{2} -  6xy + y {}^{2}

i)

 = (2x {}^{2}  + 3xy) {}^{2}

 = (2x {}^{2} ) {}^{2}  + 2 \: . \: 2x {}^{2}  \: . \: 3xy + (3xy) {}^{2}

 = 4x {}^{4}  + 12x {}^{3} y + 9x {}^{2} y {}^{2}

j)

 = (1x {}^{2} y + 1) \: . \: (1x {}^{2} y - 1)

 = (x {}^{2} y + 1) \: . \: (x {}^{2} y - 1)

 = (x {}^{2} y) {}^{2}  - 1 {}^{2}

 = x {}^{4} y {}^{2}  - 1

Att. Makaveli1996


kellenrodrigues109: obrigado
kellenrodrigues109: obrigado
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