Question

Resolva a equação a seguir: 




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Answer 1

$\frac{x-5}{10}+\frac{1-2x}{5}=\frac{3-x}{4}$

$\frac{2x-10}{20}+\frac{4-8x}{20}= \frac{15-5x}{20}$

$2x-10+4-8x=15-5x$

$2x-8x+5x=15+10-4$

$-x=21$

$x=-21$

Answer 2

Resposta:

e a primeira x-21

Explicação passo-a-passo:

\frac{x-5}{10}+\frac{1-2x}{5}=\frac{3-x}{4}

10

x−5

+

5

1−2x

=

4

3−x

\frac{2x-10}{20}+\frac{4-8x}{20}= \frac{15-5x}{20}

20

2x−10

+

20

4−8x

=

20

15−5x

2x-10+4-8x=15-5x2x−10+4−8x=15−5x

2x-8x+5x=15+10-42x−8x+5x=15+10−4

-x=21−x=21

x=-21x=−21