Question

Se A= x^2-3x+2 e B=x+2 resolva:

A)A . B
B)A+B

2)Se (x+y)^2 = 144 e x^2 +y^2 = 104, determine:

A)x+y
B)x . y

Answer 1

A.B
x²-3x+2*x+2
x²-3x+2x+2
x²-3x+2x+2+2
x²-x+4=
x+4
A+B
x²-3x+2+x+2
x²-3x+x+2+2
x²-2x+4=
2X+4=

2°
B)
(x+y)²=144
então x²+2*x*y+y²=144
x²+y².2.x.y=144
104+2.x.y=144
2.x.y=144-104
2.x.y=40
x.y=40/2
x.y=20
resposta e x.y=20