Question

quem poder me ajudar agradeço ;)

Answer 1

a) (3x-5y)²
3x²-2.3x.5y+5y²
9x²-30xy+25y²
b) (x/2+5)²
(x+10)²
x²+2.x.10+10²
x²+20x+100=0
∆=b²-4ac
∆=20²-4.1.100
∆=400-400
∆=0
x=-b-/+√∆/2a
x=-20-0/2.1
x=-20/2
x=-10