Question

Quais as raízes da equação x² - 8x + 12 = 0 ? *

Answer 1

Resposta:

2

Explicação passo-a-passo:

x2−8x+12=0

(1)⋅x2+(−8)⋅x+(12)=0

x=−(−8)±(−8)2−4⋅(12)−−−−−−−−−−−−−√2

x=8±64−(48)−−−−−−−−√2

x=8±16−−√2

x=8±(4)2

x1=122=(2)⋅(6)(2)=6

x2=42=(2)⋅(2)(2)=2

Answer 2

Explicação passo-a-passo:

OI, TUDO JÓIA? ツ

${ \color{salmon}{\bf{\Large{{ {x}^{2} - 8x + 12 = 0} }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{ - ( - 8)\pm \sqrt{ {( - 8)}^{2} - 4 \times 1 \times 12 } }{2 \times 1} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{ - ( - 8)\pm \sqrt{ {( - 8)}^{2} - 4 \times 12} }{2 \times 1} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{ - ( - 8)\pm \sqrt{ {( - 8)}^{2} - 4 \times 12 } }{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{8\pm \sqrt{ {( - 8)}^{2} - 4 \times 12} }{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{8\pm \sqrt{64 - 4 \times 12} }{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{8\pm \sqrt{64 - 48} }{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{8\pm \sqrt{16} }{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{8\pm4}{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = \frac{8 + 4}{2} } }}}} \\ { \color{salmon}{\bf{\Large{{x = \frac{8 - 4}{2} } }}}}$

${ \color{salmon}{\bf{\Large{{x = 6} }}}} \\ { \color{salmon}{\bf{\Large{{x = 2} }}}}$

${ \color{salmon}{\bf{\Large{{\boxed{ x_{1} = 6 }} }}}} \\ { \color{salmon}{\bf{\Large{{\boxed{ x_{2} = 2}} }}}}$

$\color{plum}\text{{ \boxed{{\mathbb{ATT: ARMANDO}}}}}$