Question

dadas as funções f(x) = x² -x +1 e g(x) = x +1, calcule

 (g o f)(x)

Answer 1

$f(x)=x^2-x+1\qquad\qquad\qquad\qquad{g}(x)=x+1\\\\\\\\g\circ{f}(x)\equiv{g}[f(x)]\\\\\\\\g(x)=x+1\\\\g[f(x)]=(x^2-x+1)+1\\\\g[f(x)]=x^2-x+1+1\\\\g[f(x)]=x^2-x+2\\\\\boxed{g\circ{f}(x)=x^2-x+2}$