Question

1. A forma simplificada da expressão algébrica (15 x^2-5x)/5xy . (10 y^2)/(3x-1) resulta em:

Answer 1

Oie, Td Bom?!

$= \frac{15x {}^{2} - 5x}{5xy} \: . \: \frac{10y {}^{2} }{3x - 1}$

$= \frac{ 5x \: . \: (3x - 1)}{5xy} \: . \: \frac{10y {}^{2} }{3x - 1}$

$= \frac{5x \: . \: (3x - 1)}{xy} \: . \: \frac{2y {}^{2} }{3x - 1}$

$= \frac{5x \: . \: (3x - 1)}{x} \: . \: \frac{2y}{3x - 1}$

$= 5(3x - 1) \: . \: \frac{2y}{3x - 1}$

$= 5 \: . \: 2y$

$= 10y$

Att. Makaveli1996

Answer 2

$\frac{15x^2-5x}{5xy}\cdot \frac{10y^2}{3x-1}\\\\\frac{3x-1}{y}\cdot \frac{10y^2}{3x-1}\\\\\frac{\left(3x-1\right)\cdot \:10y^2}{y\left(3x-1\right)}\\\\\frac{10y^2}{y}\\\\10y$

• 10y